Java 8 examples to show you how to convert from Instant to LocalDateTime. Instant - LocalDateTime. The java.time.LocalDateTime has no concept of time zone, just provide a. 1: This is a conversion chart for foot length in inches (Foot and Last lengths). To switch the unit simply find the one you want on the page and click it. You can also go to the universal conversion page. 2: Enter the value you want to convert (foot length in inches). Then click the Convert Me button. 1 teaspoon instant dry yeast: 3.1 grams: 2 1/4 teaspoons instant dry yeast: 7 grams: 1 tablespoon instant dry yeast: 9.3 grams: 7 grams instant dry yeast: 21 grams fresh yeast: Cornstarch: 1 cup: 150 grams: 1 teaspoon: 3.3 grams: Flour: 1 cup all-purpose flour (USDA) 125 grams: 1 cup all-purpose flour (Gold Medal) 130 grams: 1 cup whole wheat. If the ratio of sugar to flour is more than 1/2 cup sugar to 4 cups flour, an additional packet of yeast (2+1/4 tsp) per recipe is needed. An excessive amount of sugar slows down yeast fermentation. When changing your bread recipe from cake yeast to dry yeast, any of the dry yeast types (Active Dry Yeast, Instant Yeast or Bread Machine Yeast. Meat: Cooking Time (minutes) Beef, stew meat: 20 per 450 g / 1 lb Beef, meat ball: 5 per 450 g / 1 lb Beef, dressed: 20 – 25 per 450 g / 1 lb Beef (pot roast, steak, rump, round, chuck, blade or brisket) Small Chunks.

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Convert dry instant yeast culinary measurements. Tool for converting dry yeast from any amount into other common units generally used in recipes for measuring dry yeast, or also called easy quick yeast or instant yeast portions. The dry yeast conversion tools allows making translations between Metric and US unit measuring systems. The calculator deals with any instant yeast amount or unit found in recipes with the yeast content. This instant dry yeast online web converter utility works with the following weight scaling and volume measuring units and their output values: cooking cups ( Metric vs US cup of dry yeast ), grams ( g ), dekagrams ( dkg – deca – deka ), kilograms ( kg – kilo ), ounces ( oz ), fluid ounces ( fl oz ) of dry yeast, liters ( L ), milliliters ( ml ), pounds ( lb ), grains ( gr ), quarts US ( qt ) of dry yeast, quarts dry US ( qt dry ), tablespoons ( tbl.sp ) and teaspoons ( tea.sp ) full of of dry yeast amount. Instead of an info table list this instant yeast culinary amounts converter also includes option for the dry yeast product nutritional values calculation, in a specific number, plus food dietary information of dry yeast; calories or kilocalories ( Cal equals kcal in dietary and food science ) food intake energy kilojoules ( kJ ), and values in grams ( g ) plus ounces ( oz ) for total carbohydrates, sugars, protein, lipids – fat, saturated fats, dietary fiber portion and cholesterol with Sodium in mg values that dry yeast contains. Converter for baker’s yeast active yeast (in dry form) page.

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1. I made to me very handy conversions of instant yeast type from 7 grams and 15 grams into ounces weight and teaspoons measures. Baking with instant yeast today. The values exchange went very quickly, thanks for this practical help.
   7g instant yeast equals 0.25 oz weight and that is 1/4 oz or volume 2.5 tsp of instant yeast.
   15g of instant yeast is 0.5 oz in weight or 5.3 tsp in volume of instant yeast.

   Comment from/about : Instant yeast converter 15 grams and 7 grams to teaspoons of instant yeast.

2. What is weight of one teaspoon of instant dry yeast ? = 3 grams ( 2.8g ) = 0.1 ounce net weight.

   Comment from/about : Weight of one teaspoon of instant dry yeast.

3. How many cups of nutritional yeast equals one pound?
   Thanks

   Comment from/about : Luci

Leave your comment

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Skills to Develop

• Solve dimensional analysis using metric and English units. (note: metric unit definitions will not be provided on quiz.)

It is often the case that a quantity of interest may not be easy (or even possible) to measure directly but instead must be calculated from other directly measured properties and appropriate mathematical relationships. For example, consider measuring the average speed of an athlete running sprints. This is typically accomplished by measuring the time required for the athlete to run from the starting line to the finish line, and the distance between these two lines, and then computing speed from the equation that relates these three properties:

[mathrm{speed=dfrac{distance}{time}}]

An Olympic-quality sprinter can run 100 m in approximately 10 s, corresponding to an average speed of

[mathrm{dfrac{100: m}{10: s}=10: m/s}]

Note that this simple arithmetic involves dividing the numbers of each measured quantity to yield the number of the computed quantity (100/10 = 10) and likewise dividing the units of each measured quantity to yield the unit of the computed quantity (m/s = m/s). Now, consider using this same relation to predict the time required for a person running at this speed to travel a distance of 25 m. The same relation between the three properties is used, but in this case, the two quantities provided are a speed (10 m/s) and a distance (25 m). To yield the sought property, time, the equation must be rearranged appropriately:

[mathrm{time=dfrac{distance}{speed}}]

The time can then be computed as:

[mathrm{dfrac{25: m}{10: m/s}=2.5: s}]

Again, arithmetic on the numbers (25/10 = 2.5) was accompanied by the same arithmetic on the units (m/m/s = s) to yield the number and unit of the result, 2.5 s. Note that, just as for numbers, when a unit is divided by an identical unit (in this case, m/m), the result is “1”—or, as commonly phrased, the units “cancel.”

These calculations are examples of a versatile mathematical approach known as dimensional analysis (or the factor-label method). Dimensional analysis is based on this premise: the units of quantities must be subjected to the same mathematical operations as their associated numbers. This method can be applied to computations ranging from simple unit conversions to more complex, multi-step calculations involving several different quantities.

Conversion Factors and Dimensional Analysis

A ratio of two equivalent quantities expressed with different measurement units can be used as a unit conversion factor. For example, the lengths of 2.54 cm and 1 in. are equivalent (by definition), and so a unit conversion factor may be derived from the ratio,

[mathrm{dfrac{2.54: cm}{1: in.}:(2.54: cm=1: in.): or: 2.54:dfrac{cm}{in.}}]

Several other commonly used conversion factors are given in Table (PageIndex{1}).

When we multiply a quantity (such as distance given in inches) by an appropriate unit conversion factor, we convert the quantity to an equivalent value with different units (such as distance in centimeters). For example, a basketball player’s vertical jump of 34 inches can be converted to centimeters by:

[mathrm{34: cancel{in.} times dfrac{2.54: cm}{1:cancel{in.}}=86: cm}]

Since this simple arithmetic involves quantities, the premise of dimensional analysis requires that we multiply both numbers and units. The numbers of these two quantities are multiplied to yield the number of the product quantity, 86, whereas the units are multiplied to yield

[mathrm{dfrac{in.times cm}{in.}}.]

Just as for numbers, a ratio of identical units is also numerically equal to one,

[mathrm{dfrac{in.}{in.}=1}]

and the unit product thus simplifies to cm. (When identical units divide to yield a factor of 1, they are said to “cancel.”) Using dimensional analysis, we can determine that a unit conversion factor has been set up correctly by checking to confirm that the original unit will cancel, and the result will contain the sought (converted) unit.

Example (PageIndex{1}): Using a Unit Conversion Factor

The mass of a competition Frisbee is 125 g. Convert its mass to ounces using the unit conversion factor derived from the relationship 1 oz = 28.349 g (Table (PageIndex{1})).

Solution

If we have the conversion factor, we can determine the mass in kilograms using an equation similar the one used for converting length from inches to centimeters.

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[x:mathrm{oz=125: gtimes unit: conversion: factor}nonumber]

We write the unit conversion factor in its two forms:

[mathrm{dfrac{1: oz}{28.349: g}:and:dfrac{28.349: g}{1: oz}}nonumber]

The correct unit conversion factor is the ratio that cancels the units of grams and leaves ounces.

[begin{align*}
x:ce{oz}&=mathrm{125:cancel{g}times dfrac{1: oz}{28.349:cancel{g}}}
&=mathrm{left(dfrac{125}{28.349}right):oz}
&=mathrm{4.41: oz: (three: significant: figures)}
end{align*}]

Exercise (PageIndex{1})

Convert a volume of 9.345 qt to liters.

8.844 L

Beyond simple unit conversions, the factor-label method can be used to solve more complex problems involving computations. Regardless of the details, the basic approach is the same—all the factors involved in the calculation must be appropriately oriented to insure that their labels (units) will appropriately cancel and/or combine to yield the desired unit in the result. This is why it is referred to as the factor-label method. As your study of chemistry continues, you will encounter many opportunities to apply this approach.

Example (PageIndex{2}): Computing Quantities from Measurement Results

What is the density of common antifreeze in units of g/mL? A 4.00-qt sample of the antifreeze weighs 9.26 lb.

Solution

Since (mathrm{density=dfrac{mass}{volume}}), we need to divide the mass in grams by the volume in milliliters. In general: the number of units of B = the number of units of A (times) unit conversion factor. The necessary conversion factors are given in Table 1.7.1: 1 lb = 453.59 g; 1 L = 1.0567 qt; 1 L = 1,000 mL. We can convert mass from pounds to grams in one step:

[mathrm{9.26:cancel{lb}times dfrac{453.59: g}{1:cancel{lb}}=4.20times 10^3:g}nonumber ]

We need to use two steps to convert volume from quarts to milliliters.

1. Convert quarts to liters.

[mathrm{4.00:cancel{qt}timesdfrac{1: L}{1.0567:cancel{qt}}=3.78: L}nonumber]

2. Convert liters to milliliters.

[mathrm{3.78:cancel{L}timesdfrac{1000: mL}{1:cancel{L}}=3.78times10^3:mL}nonumber]

Then,

[mathrm{density=dfrac{4.20times10^3:g}{3.78times10^3:mL}=1.11: g/mL}nonumber]

Alternatively, the calculation could be set up in a way that uses three unit conversion factors sequentially as follows:

[mathrm{dfrac{9.26:cancel{lb}}{4.00:cancel{qt}}timesdfrac{453.59: g}{1:cancel{lb}}timesdfrac{1.0567:cancel{qt}}{1:cancel{L}}timesdfrac{1:cancel{L}}{1000: mL}=1.11: g/mL}nonumber]

Exercise (PageIndex{2})

What is the volume in liters of 1.000 oz, given that 1 L = 1.0567 qt and 1 qt = 32 oz (exactly)?

(mathrm{2.956times10^{-2}:L})

Example (PageIndex{3}): Computing Quantities from Measurement Results

While being driven from Philadelphia to Atlanta, a distance of about 1250 km, a 2014 Lamborghini Aventador Roadster uses 213 L gasoline.

1. What (average) fuel economy, in miles per gallon, did the Roadster get during this trip?
2. If gasoline costs $3.80 per gallon, what was the fuel cost for this trip?

Solution

(a) We first convert distance from kilometers to miles:

[mathrm{1250: kmtimesdfrac{0.62137: mi}{1: km}=777: mi}nonumber]

and then convert volume from liters to gallons:

[mathrm{213:cancel{L}timesdfrac{1.0567:cancel{qt}}{1:cancel{L}}timesdfrac{1: gal}{4:cancel{qt}}=56.3: gal}nonumber]

Then,

[mathrm{(average): mileage=dfrac{777: mi}{56.3: gal}=13.8: miles/gallon=13.8: mpg}nonumber]

Alternatively, the calculation could be set up in a way that uses all the conversion factors sequentially, as follows:

[mathrm{dfrac{1250:cancel{km}}{213:cancel{L}}timesdfrac{0.62137: mi}{1:cancel{km}}timesdfrac{1:cancel{L}}{1.0567:cancel{qt}}timesdfrac{4:cancel{qt}}{1: gal}=13.8: mpg}nonumber ]

(b) Using the previously calculated volume in gallons, we find:

[mathrm{56.3: galtimesdfrac{$3.80}{1: gal}=$214}nonumber ]

Exercise (PageIndex{3})

A Toyota Prius Hybrid uses 59.7 L gasoline to drive from San Francisco to Seattle, a distance of 1300 km (two significant digits).

1. What (average) fuel economy, in miles per gallon, did the Prius get during this trip?
2. If gasoline costs $3.90 per gallon, what was the fuel cost for this trip?

51 mpg

$62

Units Raised to a Power

When calculating area or volume, you multiply together lengths, widths, and heights. Just like in our dimensional analysis above, our units and our numbers both undergo the mathematical operation, meaning that multiplying the quantity of length by the quantity of width also multiplies the units.

$$42cm*33cm=1386 cm^{^{2}}$$

This complicates the conversion of units, however, since our GIVEN conversion factors often only account for one dimension, not two or three. When building a conversion factor for units raised to a power, we simply raise the conversion factor to the power we want our final units in. The trick is to remember to raise the QUANTITY and UNITS by the power.

Example (PageIndex{4}): Computing Quantities from Measurement Results

Convert 5.70 L to in³.

Solution

We must first convert L to mL, which as we saw in Section 1.1, is equivalent to cm³.

Instant Convert 1 1 3 Into A Fraction

$$5.70 L*frac{1000 mL}{1 L}*frac{1 cm^{3}}{1 mL}=5700cm^{3}$$

Now, if we examine the table of conversion factors (Table (PageIndex{1})), we find that there is 16.4 cm³ in 1 in³.

$$5700cm^{3}*frac{1in^{^{3}}}{16.4cm^{3}}=347.6cm^{3}$$

We could have just as easily have done this if we hadn't been given the direct conversion factor between cm³ and in³. We simply would have had to raise the conversion factor between cm and in to the third power.

Convert 1 3 To Percentage

$$5700cm^{3}*left ( frac{1in}{2.54cm} right )^{3}=347.6in^{3}$$

The trick with this way of doing the calculation is you have to remember to apply the power to EVERYTHING:

$$left ( frac{1in}{2.54cm} right )^{3}=frac{left ( 1^{3}in^{3} right )}{2.54^{3}cm^{3}}$$

Contributors

Convert 1 3 To Percent

• Paul Flowers (University of North Carolina - Pembroke), Klaus Theopold (University of Delaware) and Richard Langley (Stephen F. Austin State University) with contributing authors. Textbook content produced by OpenStax College is licensed under a Creative Commons Attribution License 4.0 license. Download for free at http://cnx.org/contents/85abf193-2bd...a7ac8df6@9.110).

• Christy VanRooyen, Oregon Tech